Base | Representation |
---|---|
bin | 111101111110101100… |
… | …0101010110011101011 |
3 | 110201112222100201121002 |
4 | 1323331120222303223 |
5 | 4140042112340243 |
6 | 141051221305215 |
7 | 12421226235641 |
oct | 1737530526353 |
9 | 421488321532 |
10 | 133100121323 |
11 | 514a1604174 |
12 | 21966b6520b |
13 | c722242b50 |
14 | 66290d5191 |
15 | 36e00d2eb8 |
hex | 1efd62aceb |
133100121323 has 4 divisors (see below), whose sum is σ = 143338592208. Its totient is φ = 122861650440.
The previous prime is 133100121313. The next prime is 133100121347. The reversal of 133100121323 is 323121001331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133100121323 - 210 = 133100120299 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133100121295 and 133100121304.
It is not an unprimeable number, because it can be changed into a prime (133100121313) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5119235423 + ... + 5119235448.
It is an arithmetic number, because the mean of its divisors is an integer number (35834648052).
Almost surely, 2133100121323 is an apocalyptic number.
133100121323 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
133100121323 is a deficient number, since it is larger than the sum of its proper divisors (10238470885).
133100121323 is a wasteful number, since it uses less digits than its factorization.
133100121323 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10238470884.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 133100121323 its reverse (323121001331), we get a palindrome (456221122654).
The spelling of 133100121323 in words is "one hundred thirty-three billion, one hundred million, one hundred twenty-one thousand, three hundred twenty-three".
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