13310015113 has 4 divisors (see below), whose sum is σ = 13379701248. Its totient is φ = 13240328980.

The previous prime is 13310015111. The next prime is 13310015167. The reversal of 13310015113 is 31151001331.

13310015113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13310015113 - 2¹ = 13310015111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13310015111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 34842781 + ... + 34843162.

It is an arithmetic number, because the mean of its divisors is an integer number (3344925312).

Almost surely, 2^13310015113 is an apocalyptic number.

It is an amenable number.

13310015113 is a deficient number, since it is larger than the sum of its proper divisors (69686135).

13310015113 is an equidigital number, since it uses as much as digits as its factorization.

13310015113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 69686134.

The product of its (nonzero) digits is 135, while the sum is 19.

Adding to 13310015113 its reverse (31151001331), we get a palindrome (44461016444).

The spelling of 13310015113 in words is "thirteen billion, three hundred ten million, fifteen thousand, one hundred thirteen".