Base | Representation |
---|---|
bin | 100111101010101… |
… | …1100000101011001 |
3 | 10102202112211100112 |
4 | 1033111130011121 |
5 | 10211220120441 |
6 | 340024214105 |
7 | 44661325064 |
oct | 11725340531 |
9 | 3382484315 |
10 | 1331020121 |
11 | 623365132 |
12 | 31190a335 |
13 | 1829a9392 |
14 | c8ab78db |
15 | 7bcbb4eb |
hex | 4f55c159 |
1331020121 has 8 divisors (see below), whose sum is σ = 1350306720. Its totient is φ = 1311811072.
The previous prime is 1331020109. The next prime is 1331020133. The reversal of 1331020121 is 1210201331.
It is an interprime number because it is at equal distance from previous prime (1331020109) and next prime (1331020133).
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1331020121 is a prime.
It is a super-4 number, since 4×13310201214 (a number of 38 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1331020096 and 1331020105.
It is not an unprimeable number, because it can be changed into a prime (1331020421) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15641 + ... + 53913.
It is an arithmetic number, because the mean of its divisors is an integer number (168788340).
Almost surely, 21331020121 is an apocalyptic number.
It is an amenable number.
1331020121 is a deficient number, since it is larger than the sum of its proper divisors (19286599).
1331020121 is an equidigital number, since it uses as much as digits as its factorization.
1331020121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 38775.
The product of its (nonzero) digits is 36, while the sum is 14.
The square root of 1331020121 is about 36483.1484524020. The cubic root of 1331020121 is about 1100.0055429473.
Adding to 1331020121 its reverse (1210201331), we get a palindrome (2541221452).
The spelling of 1331020121 in words is "one billion, three hundred thirty-one million, twenty thousand, one hundred twenty-one".
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