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13310201441 = 67251791473
BaseRepresentation
bin11000110010101100…
…11000111001100001
31021100121111021211202
430121112120321201
5204224402421231
610040431450545
7650560563005
oct143126307141
937317437752
1013310201441
115710297389
1226b5686a55
131341731c54
14903a36705
1552d7c85cb
hex319598e61

13310201441 has 8 divisors (see below), whose sum is σ = 13562698464. Its totient is φ = 13059288000.

The previous prime is 13310201417. The next prime is 13310201479. The reversal of 13310201441 is 14410201331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13310201441 - 218 = 13309939297 is a prime.

It is a super-2 number, since 2×133102014412 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13310201491) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 378920 + ... + 412553.

It is an arithmetic number, because the mean of its divisors is an integer number (1695337308).

Almost surely, 213310201441 is an apocalyptic number.

It is an amenable number.

13310201441 is a deficient number, since it is larger than the sum of its proper divisors (252497023).

13310201441 is an equidigital number, since it uses as much as digits as its factorization.

13310201441 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 791791.

The product of its (nonzero) digits is 288, while the sum is 20.

Adding to 13310201441 its reverse (14410201331), we get a palindrome (27720402772).

The spelling of 13310201441 in words is "thirteen billion, three hundred ten million, two hundred one thousand, four hundred forty-one".

Divisors: 1 67 251 16817 791473 53028691 198659723 13310201441