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13310204020003 = 111210018547273
BaseRepresentation
bin1100000110110000010111…
…1110111000010100100011
31202010102222000002110222101
43001230011332320110203
53221033244212120003
644150342345151231
72542426156305352
oct301540576702443
952112860073871
1013310204020003
11427190a19a280
1215ab73448b517
137571ba838487
14340308437999
15181367aa411d
hexc1b05fb8523

13310204020003 has 4 divisors (see below), whose sum is σ = 14520222567288. Its totient is φ = 12100185472720.

The previous prime is 13310204019991. The next prime is 13310204020019. The reversal of 13310204020003 is 30002040201331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13310204020003 - 29 = 13310204019491 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13310204020103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 605009273626 + ... + 605009273647.

It is an arithmetic number, because the mean of its divisors is an integer number (3630055641822).

Almost surely, 213310204020003 is an apocalyptic number.

13310204020003 is a deficient number, since it is larger than the sum of its proper divisors (1210018547285).

13310204020003 is a wasteful number, since it uses less digits than its factorization.

13310204020003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1210018547284.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 13310204020003 its reverse (30002040201331), we get a palindrome (43312244221334).

The spelling of 13310204020003 in words is "thirteen trillion, three hundred ten billion, two hundred four million, twenty thousand, three".

Divisors: 1 11 1210018547273 13310204020003