Base | Representation |
---|---|
bin | 11000110010101110… |
… | …01001011110010011 |
3 | 1021100121212101202201 |
4 | 30121113021132103 |
5 | 204224430303103 |
6 | 10040440024031 |
7 | 650562352036 |
oct | 143127113623 |
9 | 37317771681 |
10 | 13310400403 |
11 | 5710412913 |
12 | 26b5762017 |
13 | 13417a1691 |
14 | 903a8901d |
15 | 52d81751d |
hex | 3195c9793 |
13310400403 has 4 divisors (see below), whose sum is σ = 13889113488. Its totient is φ = 12731687320.
The previous prime is 13310400401. The next prime is 13310400409. The reversal of 13310400403 is 30400401331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13310400403 - 21 = 13310400401 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13310400401) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 289356508 + ... + 289356553.
It is an arithmetic number, because the mean of its divisors is an integer number (3472278372).
Almost surely, 213310400403 is an apocalyptic number.
13310400403 is a deficient number, since it is larger than the sum of its proper divisors (578713085).
13310400403 is an equidigital number, since it uses as much as digits as its factorization.
13310400403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 578713084.
The product of its (nonzero) digits is 432, while the sum is 19.
Adding to 13310400403 its reverse (30400401331), we get a palindrome (43710801734).
The spelling of 13310400403 in words is "thirteen billion, three hundred ten million, four hundred thousand, four hundred three".
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