Base | Representation |
---|---|
bin | 1100000110110001001001… |
… | …1110100010010101101011 |
3 | 1202010110111121112112122012 |
4 | 3001230102132202111223 |
5 | 3221034211343121123 |
6 | 44150415234150135 |
7 | 2542434313141415 |
oct | 301542236422553 |
9 | 52113447475565 |
10 | 13310413645163 |
11 | 4271a07556808 |
12 | 15ab79272234b |
13 | 7572220b282b |
14 | 3403282039b5 |
15 | 18137b1b0378 |
hex | c1b127a256b |
13310413645163 has 4 divisors (see below), whose sum is σ = 14093379153720. Its totient is φ = 12527448136608.
The previous prime is 13310413645117. The next prime is 13310413645189. The reversal of 13310413645163 is 36154631401331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13310413645163 - 222 = 13310409450859 is a prime.
It is a super-2 number, since 2×133104136451632 (a number of 27 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 13310413645163.
It is not an unprimeable number, because it can be changed into a prime (13310413645103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 391482754253 + ... + 391482754286.
It is an arithmetic number, because the mean of its divisors is an integer number (3523344788430).
Almost surely, 213310413645163 is an apocalyptic number.
13310413645163 is a deficient number, since it is larger than the sum of its proper divisors (782965508557).
13310413645163 is an equidigital number, since it uses as much as digits as its factorization.
13310413645163 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 782965508556.
The product of its (nonzero) digits is 233280, while the sum is 41.
The spelling of 13310413645163 in words is "thirteen trillion, three hundred ten billion, four hundred thirteen million, six hundred forty-five thousand, one hundred sixty-three".
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