Base | Representation |
---|---|
bin | 1100000110110001001110… |
… | …1001111111010000010011 |
3 | 1202010110112222202102122122 |
4 | 3001230103221333100103 |
5 | 3221034231424040103 |
6 | 44150421222124455 |
7 | 2542434643231013 |
oct | 301542351772023 |
9 | 52113488672578 |
10 | 13310433424403 |
11 | 4271a17736195 |
12 | 15ab79928072b |
13 | 75722621961b |
14 | 34032aab1c43 |
15 | 18137ccbab38 |
hex | c1b13a7f413 |
13310433424403 has 4 divisors (see below), whose sum is σ = 13313325115608. Its totient is φ = 13307541733200.
The previous prime is 13310433424271. The next prime is 13310433424427. The reversal of 13310433424403 is 30442433401331.
13310433424403 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13310433424403 - 28 = 13310433424147 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13310433414403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1445838698 + ... + 1445847903.
It is an arithmetic number, because the mean of its divisors is an integer number (3328331278902).
Almost surely, 213310433424403 is an apocalyptic number.
13310433424403 is a deficient number, since it is larger than the sum of its proper divisors (2891691205).
13310433424403 is an equidigital number, since it uses as much as digits as its factorization.
13310433424403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2891691204.
The product of its (nonzero) digits is 124416, while the sum is 35.
Adding to 13310433424403 its reverse (30442433401331), we get a palindrome (43752866825734).
The spelling of 13310433424403 in words is "thirteen trillion, three hundred ten billion, four hundred thirty-three million, four hundred twenty-four thousand, four hundred three".
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