Search a number
-
+
13311303121 = 54412446481
BaseRepresentation
bin11000110010110101…
…00101110111010001
31021100200120021001201
430121122211313101
5204230143144441
610040511231201
7650603131624
oct143132456721
937320507051
1013311303121
11571097a066
1226b5b18501
131341a2952c
14903c41dbb
1552d944c31
hex3196a5dd1

13311303121 has 4 divisors (see below), whose sum is σ = 13313755044. Its totient is φ = 13308851200.

The previous prime is 13311303077. The next prime is 13311303133. The reversal of 13311303121 is 12130311331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 9987204096 + 3324099025 = 99936^2 + 57655^2 .

It is a cyclic number.

It is not a de Polignac number, because 13311303121 - 221 = 13309205969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13311304121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1217800 + ... + 1228681.

It is an arithmetic number, because the mean of its divisors is an integer number (3328438761).

Almost surely, 213311303121 is an apocalyptic number.

It is an amenable number.

13311303121 is a deficient number, since it is larger than the sum of its proper divisors (2451923).

13311303121 is an equidigital number, since it uses as much as digits as its factorization.

13311303121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2451922.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 13311303121 its reverse (12130311331), we get a palindrome (25441614452).

The spelling of 13311303121 in words is "thirteen billion, three hundred eleven million, three hundred three thousand, one hundred twenty-one".

Divisors: 1 5441 2446481 13311303121