Base | Representation |
---|---|
bin | 10011010111101101100… |
… | …101110010100010101011 |
3 | 11201020212210211011022022 |
4 | 103113231211302202223 |
5 | 133302124014013003 |
6 | 2455302501015055 |
7 | 165112444551266 |
oct | 23275545624253 |
9 | 4636783734268 |
10 | 1331131001003 |
11 | 473590824aa1 |
12 | 195b950b448b |
13 | 986a98a59ab |
14 | 485d9cc1cdd |
15 | 2495beaa738 |
hex | 135ed9728ab |
1331131001003 has 4 divisors (see below), whose sum is σ = 1331944155360. Its totient is φ = 1330317846648.
The previous prime is 1331131000967. The next prime is 1331131001059. The reversal of 1331131001003 is 3001001311331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1331131001003 - 214 = 1331130984619 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1331131001503) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 406574723 + ... + 406577996.
It is an arithmetic number, because the mean of its divisors is an integer number (332986038840).
Almost surely, 21331131001003 is an apocalyptic number.
1331131001003 is a deficient number, since it is larger than the sum of its proper divisors (813154357).
1331131001003 is an equidigital number, since it uses as much as digits as its factorization.
1331131001003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 813154356.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 1331131001003 its reverse (3001001311331), we get a palindrome (4332132312334).
The spelling of 1331131001003 in words is "one trillion, three hundred thirty-one billion, one hundred thirty-one million, one thousand, three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •