13311314434401 has 4 divisors (see below), whose sum is σ = 17748419245872. Its totient is φ = 8874209622932.

The previous prime is 13311314434399. The next prime is 13311314434417. The reversal of 13311314434401 is 10443441311331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13311314434401 - 2¹ = 13311314434399 is a prime.

It is not an unprimeable number, because it can be changed into a prime (13311314434421) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2218552405731 + ... + 2218552405736.

It is an arithmetic number, because the mean of its divisors is an integer number (4437104811468).

Almost surely, 2^{13311314434401} is an apocalyptic number.

It is an amenable number.

13311314434401 is a deficient number, since it is larger than the sum of its proper divisors (4437104811471).

13311314434401 is an equidigital number, since it uses as much as digits as its factorization.

13311314434401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4437104811470.

The product of its (nonzero) digits is 20736, while the sum is 33.

Adding to 13311314434401 its reverse (10443441311331), we get a palindrome (23754755745732).

The spelling of 13311314434401 in words is "thirteen trillion, three hundred eleven billion, three hundred fourteen million, four hundred thirty-four thousand, four hundred one".