Search a number
-
+
133120133124403 = 355155137482253
BaseRepresentation
bin11110010001001001110010…
…001111110101000100110011
3122110100011022221221121001211
4132101021302033311010303
5114422020013034440103
61151042313411140551
740016416665524005
oct3621116217650463
9573304287847054
10133120133124403
1139463a27794397
1212b1b6a72a4757
135938236a40089
1424c3097d72375
15105cb607dc36d
hex7912723f5133

133120133124403 has 4 divisors (see below), whose sum is σ = 133120174158208. Its totient is φ = 133120092090600.

The previous prime is 133120133124371. The next prime is 133120133124409. The reversal of 133120133124403 is 304421331021331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133120133124403 - 25 = 133120133124371 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133120133124409) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15189576 + ... + 22292677.

It is an arithmetic number, because the mean of its divisors is an integer number (33280043539552).

Almost surely, 2133120133124403 is an apocalyptic number.

133120133124403 is a deficient number, since it is larger than the sum of its proper divisors (41033805).

133120133124403 is an equidigital number, since it uses as much as digits as its factorization.

133120133124403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 41033804.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 133120133124403 its reverse (304421331021331), we get a palindrome (437541464145734).

The spelling of 133120133124403 in words is "one hundred thirty-three trillion, one hundred twenty billion, one hundred thirty-three million, one hundred twenty-four thousand, four hundred three".

Divisors: 1 3551551 37482253 133120133124403