Base | Representation |
---|---|
bin | 11110010001001001110010… |
… | …001111110101000100110011 |
3 | 122110100011022221221121001211 |
4 | 132101021302033311010303 |
5 | 114422020013034440103 |
6 | 1151042313411140551 |
7 | 40016416665524005 |
oct | 3621116217650463 |
9 | 573304287847054 |
10 | 133120133124403 |
11 | 39463a27794397 |
12 | 12b1b6a72a4757 |
13 | 5938236a40089 |
14 | 24c3097d72375 |
15 | 105cb607dc36d |
hex | 7912723f5133 |
133120133124403 has 4 divisors (see below), whose sum is σ = 133120174158208. Its totient is φ = 133120092090600.
The previous prime is 133120133124371. The next prime is 133120133124409. The reversal of 133120133124403 is 304421331021331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133120133124403 - 25 = 133120133124371 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133120133124409) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15189576 + ... + 22292677.
It is an arithmetic number, because the mean of its divisors is an integer number (33280043539552).
Almost surely, 2133120133124403 is an apocalyptic number.
133120133124403 is a deficient number, since it is larger than the sum of its proper divisors (41033805).
133120133124403 is an equidigital number, since it uses as much as digits as its factorization.
133120133124403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 41033804.
The product of its (nonzero) digits is 15552, while the sum is 31.
Adding to 133120133124403 its reverse (304421331021331), we get a palindrome (437541464145734).
The spelling of 133120133124403 in words is "one hundred thirty-three trillion, one hundred twenty billion, one hundred thirty-three million, one hundred twenty-four thousand, four hundred three".
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