1331300201131 has 4 divisors (see below), whose sum is σ = 1334477529000. Its totient is φ = 1328122873264.

The previous prime is 1331300201053. The next prime is 1331300201221. The reversal of 1331300201131 is 1311020031331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1331300201131 - 2⁷ = 1331300201003 is a prime.

It is a super-2 number, since 2×1331300201131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1331300201099 and 1331300201108.

It is not an unprimeable number, because it can be changed into a prime (1331300201431) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1588663306 + ... + 1588664143.

It is an arithmetic number, because the mean of its divisors is an integer number (333619382250).

Almost surely, 2^{1331300201131} is an apocalyptic number.

1331300201131 is a deficient number, since it is larger than the sum of its proper divisors (3177327869).

1331300201131 is an equidigital number, since it uses as much as digits as its factorization.

1331300201131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3177327868.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1331300201131 its reverse (1311020031331), we get a palindrome (2642320232462).

The spelling of 1331300201131 in words is "one trillion, three hundred thirty-one billion, three hundred million, two hundred one thousand, one hundred thirty-one".