13313100112113 has 4 divisors (see below), whose sum is σ = 17750800149488. Its totient is φ = 8875400074740.

The previous prime is 13313100112087. The next prime is 13313100112121. The reversal of 13313100112113 is 31121100131331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 13313100112113 - 2¹⁸ = 13313099849969 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 13313100112113.

It is not an unprimeable number, because it can be changed into a prime (13313100112133) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2218850018683 + ... + 2218850018688.

It is an arithmetic number, because the mean of its divisors is an integer number (4437700037372).

Almost surely, 2^{13313100112113} is an apocalyptic number.

It is an amenable number.

13313100112113 is a deficient number, since it is larger than the sum of its proper divisors (4437700037375).

13313100112113 is an equidigital number, since it uses as much as digits as its factorization.

13313100112113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4437700037374.

The product of its (nonzero) digits is 162, while the sum is 21.

Adding to 13313100112113 its reverse (31121100131331), we get a palindrome (44434200243444).

The spelling of 13313100112113 in words is "thirteen trillion, three hundred thirteen billion, one hundred million, one hundred twelve thousand, one hundred thirteen".