Base | Representation |
---|---|
bin | 10011010111111000010… |
… | …000101100011000010001 |
3 | 11201021100021200021100201 |
4 | 103113320100230120101 |
5 | 133303010331120423 |
6 | 2455332334015201 |
7 | 165120050313013 |
oct | 23277020543021 |
9 | 4637307607321 |
10 | 1331310020113 |
11 | 473672887777 |
12 | 196025047501 |
13 | 987079c5268 |
14 | 486159a21b3 |
15 | 2496ca6d2ad |
hex | 135f842c611 |
1331310020113 has 4 divisors (see below), whose sum is σ = 1401378968560. Its totient is φ = 1261241071668.
The previous prime is 1331310020111. The next prime is 1331310020137. The reversal of 1331310020113 is 3110200131331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 1331310020113 - 21 = 1331310020111 is a prime.
It is a super-3 number, since 3×13313100201133 (a number of 37 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (19), and also a Moran number because the ratio is a prime number: 70068948427 = 1331310020113 / (1 + 3 + 3 + 1 + 3 + 1 + 0 + 0 + 2 + 0 + 1 + 1 + 3).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1331310020111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 35034474195 + ... + 35034474232.
It is an arithmetic number, because the mean of its divisors is an integer number (350344742140).
Almost surely, 21331310020113 is an apocalyptic number.
It is an amenable number.
1331310020113 is a deficient number, since it is larger than the sum of its proper divisors (70068948447).
1331310020113 is an equidigital number, since it uses as much as digits as its factorization.
1331310020113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 70068948446.
The product of its (nonzero) digits is 162, while the sum is 19.
Adding to 1331310020113 its reverse (3110200131331), we get a palindrome (4441510151444).
The spelling of 1331310020113 in words is "one trillion, three hundred thirty-one billion, three hundred ten million, twenty thousand, one hundred thirteen".
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