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13313120033 = 14399251647
BaseRepresentation
bin11000110011000011…
…00001011100100001
31021100210222120101202
430121201201130201
5204231124320113
610041014210545
7650624440013
oct143141413441
937323876352
1013313120033
115711a00144
1226b6653a55
131342214525
149041961b3
1552dba3258
hex319861721

13313120033 has 4 divisors (see below), whose sum is σ = 13322373120. Its totient is φ = 13303866948.

The previous prime is 13313120021. The next prime is 13313120047. The reversal of 13313120033 is 33002131331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13313120033 - 210 = 13313119009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13313119987 and 13313120014.

It is not an unprimeable number, because it can be changed into a prime (13313140033) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 4624385 + ... + 4627262.

It is an arithmetic number, because the mean of its divisors is an integer number (3330593280).

Almost surely, 213313120033 is an apocalyptic number.

It is an amenable number.

13313120033 is a deficient number, since it is larger than the sum of its proper divisors (9253087).

13313120033 is an equidigital number, since it uses as much as digits as its factorization.

13313120033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 9253086.

The product of its (nonzero) digits is 486, while the sum is 20.

Adding to 13313120033 its reverse (33002131331), we get a palindrome (46315251364).

The spelling of 13313120033 in words is "thirteen billion, three hundred thirteen million, one hundred twenty thousand, thirty-three".

Divisors: 1 1439 9251647 13313120033