1331321121131 has 4 divisors (see below), whose sum is σ = 1331323952232. Its totient is φ = 1331318290032.

The previous prime is 1331321121083. The next prime is 1331321121157. The reversal of 1331321121131 is 1311211231331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1331321121131 is a prime.

It is a super-2 number, since 2×1331321121131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1331321121097 and 1331321121106.

It is not an unprimeable number, because it can be changed into a prime (1331321121331) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 522281 + ... + 1713306.

It is an arithmetic number, because the mean of its divisors is an integer number (332830988058).

Almost surely, 2^{1331321121131} is an apocalyptic number.

1331321121131 is a deficient number, since it is larger than the sum of its proper divisors (2831101).

1331321121131 is an equidigital number, since it uses as much as digits as its factorization.

1331321121131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2831100.

The product of its digits is 324, while the sum is 23.

Adding to 1331321121131 its reverse (1311211231331), we get a palindrome (2642532352462).

The spelling of 1331321121131 in words is "one trillion, three hundred thirty-one billion, three hundred twenty-one million, one hundred twenty-one thousand, one hundred thirty-one".