Base | Representation |
---|---|
bin | 1100000110111110100100… |
… | …0100111111011101001011 |
3 | 1202010210210112100001202001 |
4 | 3001233221010333131023 |
5 | 3221114100044100443 |
6 | 44152212411251431 |
7 | 2542622452111033 |
oct | 301575104773513 |
9 | 52123715301661 |
10 | 13314014050123 |
11 | 42734949212a6 |
12 | 15b0418449b77 |
13 | 757676ca5077 |
14 | 34058a45a8c3 |
15 | 1814dc301d4d |
hex | c1be913f74b |
13314014050123 has 16 divisors (see below), whose sum is σ = 13655643148224. Its totient is φ = 12973195146240.
The previous prime is 13314014050049. The next prime is 13314014050147. The reversal of 13314014050123 is 32105041041331.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13314014050123 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13314014050091 and 13314014050100.
It is not an unprimeable number, because it can be changed into a prime (13314014950123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 209978461 + ... + 210041857.
It is an arithmetic number, because the mean of its divisors is an integer number (853477696764).
Almost surely, 213314014050123 is an apocalyptic number.
13314014050123 is a deficient number, since it is larger than the sum of its proper divisors (341629098101).
13314014050123 is an equidigital number, since it uses as much as digits as its factorization.
13314014050123 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 69702.
The product of its (nonzero) digits is 4320, while the sum is 28.
Adding to 13314014050123 its reverse (32105041041331), we get a palindrome (45419055091454).
The spelling of 13314014050123 in words is "thirteen trillion, three hundred fourteen billion, fourteen million, fifty thousand, one hundred twenty-three".
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