Base | Representation |
---|---|
bin | 111110000000000000… |
… | …0100100000110011001 |
3 | 110201200001011210200202 |
4 | 1330000000210012121 |
5 | 4140134344242131 |
6 | 141055432511545 |
7 | 12422302315622 |
oct | 1740000440631 |
9 | 421601153622 |
10 | 133144134041 |
11 | 51514435616 |
12 | 2197984b5b5 |
13 | c72b3b2c89 |
14 | 6630cb0a49 |
15 | 36e3dc8bcb |
hex | 1f00024199 |
133144134041 has 8 divisors (see below), whose sum is σ = 134125622400. Its totient is φ = 132162785568.
The previous prime is 133144134017. The next prime is 133144134091. The reversal of 133144134041 is 140431441331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-133144134041 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133144133995 and 133144134013.
It is not an unprimeable number, because it can be changed into a prime (133144134091) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2606060 + ... + 2656658.
It is an arithmetic number, because the mean of its divisors is an integer number (16765702800).
Almost surely, 2133144134041 is an apocalyptic number.
It is an amenable number.
133144134041 is a deficient number, since it is larger than the sum of its proper divisors (981488359).
133144134041 is a wasteful number, since it uses less digits than its factorization.
133144134041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 69943.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 133144134041 its reverse (140431441331), we get a palindrome (273575575372).
The spelling of 133144134041 in words is "one hundred thirty-three billion, one hundred forty-four million, one hundred thirty-four thousand, forty-one".
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