Base | Representation |
---|---|
bin | 11110010001100000011110… |
… | …110101000100100111101011 |
3 | 122110102111020100221010022012 |
4 | 132101200132311010213223 |
5 | 114422414420332430120 |
6 | 1151101423534550135 |
7 | 40021241625506603 |
oct | 3621403665044753 |
9 | 573374210833265 |
10 | 133144503405035 |
11 | 394732a3113991 |
12 | 12b2436896834b |
13 | 593a61b973685 |
14 | 24c432a837c03 |
15 | 105d5da0711c5 |
hex | 79181ed449eb |
133144503405035 has 8 divisors (see below), whose sum is σ = 162158081759376. Its totient is φ = 104925817608480.
The previous prime is 133144503405019. The next prime is 133144503405041. The reversal of 133144503405035 is 530504305441331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 133144503405035 - 24 = 133144503405019 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 133144503404983 and 133144503405001.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 198723139076 + ... + 198723139745.
It is an arithmetic number, because the mean of its divisors is an integer number (20269760219922).
Almost surely, 2133144503405035 is an apocalyptic number.
133144503405035 is a deficient number, since it is larger than the sum of its proper divisors (29013578354341).
133144503405035 is an equidigital number, since it uses as much as digits as its factorization.
133144503405035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 397446278893.
The product of its (nonzero) digits is 648000, while the sum is 41.
Adding to 133144503405035 its reverse (530504305441331), we get a palindrome (663648808846366).
The spelling of 133144503405035 in words is "one hundred thirty-three trillion, one hundred forty-four billion, five hundred three million, four hundred five thousand, thirty-five".
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