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13320030001 = 24115524691
BaseRepresentation
bin11000110011110111…
…11000011100110001
31021101021222122002111
430121323320130301
5204234411430001
610041422245321
7651040246465
oct143173703461
937337878074
1013320030001
11571589a763
1226b8a26841
131343793775
149050744a5
1552e5ba851
hex319ef8731

13320030001 has 4 divisors (see below), whose sum is σ = 13325557104. Its totient is φ = 13314502900.

The previous prime is 13320029999. The next prime is 13320030037. The reversal of 13320030001 is 10003002331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10003002331 = 71429000333.

It is a cyclic number.

It is not a de Polignac number, because 13320030001 - 21 = 13320029999 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13320030041) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2759935 + ... + 2764756.

It is an arithmetic number, because the mean of its divisors is an integer number (3331389276).

Almost surely, 213320030001 is an apocalyptic number.

It is an amenable number.

13320030001 is a deficient number, since it is larger than the sum of its proper divisors (5527103).

13320030001 is an equidigital number, since it uses as much as digits as its factorization.

13320030001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5527102.

The product of its (nonzero) digits is 54, while the sum is 13.

Adding to 13320030001 its reverse (10003002331), we get a palindrome (23323032332).

The spelling of 13320030001 in words is "thirteen billion, three hundred twenty million, thirty thousand, one".

Divisors: 1 2411 5524691 13320030001