1332011022001 has 4 divisors (see below), whose sum is σ = 1453102933104. Its totient is φ = 1210919110900.

The previous prime is 1332011021981. The next prime is 1332011022019. The reversal of 1332011022001 is 1002201102331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1332011022001 - 2⁵ = 1332011021969 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1332011022101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60545955535 + ... + 60545955556.

It is an arithmetic number, because the mean of its divisors is an integer number (363275733276).

Almost surely, 2^{1332011022001} is an apocalyptic number.

1332011022001 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1332011022001 is a deficient number, since it is larger than the sum of its proper divisors (121091911103).

1332011022001 is a wasteful number, since it uses less digits than its factorization.

1332011022001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 121091911102.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1332011022001 its reverse (1002201102331), we get a palindrome (2334212124332).

The spelling of 1332011022001 in words is "one trillion, three hundred thirty-two billion, eleven million, twenty-two thousand, one".