Base | Representation |
---|---|
bin | 1100000111010101101110… |
… | …1001111101101011110001 |
3 | 1202011101211211012200211122 |
4 | 3001311123221331223301 |
5 | 3221214313203441423 |
6 | 44155121344552025 |
7 | 2543232515010215 |
oct | 301653351755361 |
9 | 52141754180748 |
10 | 13320231312113 |
11 | 4276095355250 |
12 | 15b1672622615 |
13 | 75812809020b |
14 | 3409ba062945 |
15 | 1817530538c8 |
hex | c1d5ba7daf1 |
13320231312113 has 16 divisors (see below), whose sum is σ = 15282344411136. Its totient is φ = 11491606581840.
The previous prime is 13320231312109. The next prime is 13320231312121. The reversal of 13320231312113 is 31121313202331.
It is not a de Polignac number, because 13320231312113 - 22 = 13320231312109 is a prime.
It is a super-2 number, since 2×133202313121132 (a number of 27 digits) contains 22 as substring.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13320231312133) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 207247931 + ... + 207312192.
It is an arithmetic number, because the mean of its divisors is an integer number (955146525696).
Almost surely, 213320231312113 is an apocalyptic number.
It is an amenable number.
13320231312113 is a deficient number, since it is larger than the sum of its proper divisors (1962113099023).
13320231312113 is a wasteful number, since it uses less digits than its factorization.
13320231312113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 414560284.
The product of its (nonzero) digits is 1944, while the sum is 26.
Adding to 13320231312113 its reverse (31121313202331), we get a palindrome (44441544514444).
The spelling of 13320231312113 in words is "thirteen trillion, three hundred twenty billion, two hundred thirty-one million, three hundred twelve thousand, one hundred thirteen".
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