13320233241041 has 4 divisors (see below), whose sum is σ = 13320247519332. Its totient is φ = 13320218962752.

The previous prime is 13320233241019. The next prime is 13320233241047. The reversal of 13320233241041 is 14014233202331.

13320233241041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 3437408700625 + 9882824540416 = 1854025^2 + 3143696^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13320233241041 is a prime.

It is a super-2 number, since 2×13320233241041² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13320233240995 and 13320233241013.

It is not an unprimeable number, because it can be changed into a prime (13320233241047) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5634020 + ... + 7640853.

It is an arithmetic number, because the mean of its divisors is an integer number (3330061879833).

Almost surely, 2^{13320233241041} is an apocalyptic number.

It is an amenable number.

13320233241041 is a deficient number, since it is larger than the sum of its proper divisors (14278291).

13320233241041 is a wasteful number, since it uses less digits than its factorization.

13320233241041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 14278290.

The product of its (nonzero) digits is 10368, while the sum is 29.

Adding to 13320233241041 its reverse (14014233202331), we get a palindrome (27334466443372).

The spelling of 13320233241041 in words is "thirteen trillion, three hundred twenty billion, two hundred thirty-three million, two hundred forty-one thousand, forty-one".