Base | Representation |
---|---|
bin | 1100000111010101110001… |
… | …1010110111100111010001 |
3 | 1202011101212201100000211120 |
4 | 3001311130122313213101 |
5 | 3221214324444213210 |
6 | 44155122523432453 |
7 | 2543233031663655 |
oct | 301653432674721 |
9 | 52141781300746 |
10 | 13320244132305 |
11 | 42760a1611250 |
12 | 15b1676985729 |
13 | 75812a92b626 |
14 | 3409bba3ca65 |
15 | 181754237270 |
hex | c1d5c6b79d1 |
13320244132305 has 128 divisors (see below), whose sum is σ = 23673239470080. Its totient is φ = 6341361903360.
The previous prime is 13320244132291. The next prime is 13320244132337. The reversal of 13320244132305 is 50323144202331.
It is not a de Polignac number, because 13320244132305 - 24 = 13320244132289 is a prime.
It is a super-2 number, since 2×133202441323052 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (33).
It is an unprimeable number.
It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 8227450786 + ... + 8227452404.
It is an arithmetic number, because the mean of its divisors is an integer number (184947183360).
Almost surely, 213320244132305 is an apocalyptic number.
13320244132305 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13320244132305 is a deficient number, since it is larger than the sum of its proper divisors (10352995337775).
13320244132305 is a wasteful number, since it uses less digits than its factorization.
13320244132305 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3651.
The product of its (nonzero) digits is 51840, while the sum is 33.
Adding to 13320244132305 its reverse (50323144202331), we get a palindrome (63643388334636).
The spelling of 13320244132305 in words is "thirteen trillion, three hundred twenty billion, two hundred forty-four million, one hundred thirty-two thousand, three hundred five".
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