1332033342121 has 4 divisors (see below), whose sum is σ = 1332046988244. Its totient is φ = 1332019696000.

The previous prime is 1332033342103. The next prime is 1332033342127. The reversal of 1332033342121 is 1212433302331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1044608687721 + 287424654400 = 1022061^2 + 536120^2 .

It is a cyclic number.

It is not a de Polignac number, because 1332033342121 - 2⁹ = 1332033341609 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1332033342121.

It is not an unprimeable number, because it can be changed into a prime (1332033342127) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6675580 + ... + 6872221.

It is an arithmetic number, because the mean of its divisors is an integer number (333011747061).

Almost surely, 2^{1332033342121} is an apocalyptic number.

It is an amenable number.

1332033342121 is a deficient number, since it is larger than the sum of its proper divisors (13646123).

1332033342121 is an equidigital number, since it uses as much as digits as its factorization.

1332033342121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13646122.

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 1332033342121 its reverse (1212433302331), we get a palindrome (2544466644452).

The spelling of 1332033342121 in words is "one trillion, three hundred thirty-two billion, thirty-three million, three hundred forty-two thousand, one hundred twenty-one".