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133204020131 = 7131463780441
BaseRepresentation
bin111110000001110010…
…1000000101110100011
3110201211012212022222002
41330003211000232203
54140300212121011
6141105412234215
712423630326630
oct1740345005643
9421735768862
10133204020131
1151545218956
122199590b96b
13c73a920130
146638c1d187
1536e92a7c3b
hex1f03940ba3

133204020131 has 8 divisors (see below), whose sum is σ = 163943409504. Its totient is φ = 105392191680.

The previous prime is 133204020113. The next prime is 133204020203. The reversal of 133204020131 is 131020402331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-133204020131 is a prime.

It is a super-2 number, since 2×1332040201312 (a number of 23 digits) contains 22 as substring.

It is not an unprimeable number, because it can be changed into a prime (133204022131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 731890130 + ... + 731890311.

It is an arithmetic number, because the mean of its divisors is an integer number (20492926188).

Almost surely, 2133204020131 is an apocalyptic number.

133204020131 is a deficient number, since it is larger than the sum of its proper divisors (30739389373).

133204020131 is a wasteful number, since it uses less digits than its factorization.

133204020131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1463780461.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 133204020131 its reverse (131020402331), we get a palindrome (264224422462).

The spelling of 133204020131 in words is "one hundred thirty-three billion, two hundred four million, twenty thousand, one hundred thirty-one".

Divisors: 1 7 13 91 1463780441 10246463087 19029145733 133204020131