13320431433 has 6 divisors (see below), whose sum is σ = 19240623194. Its totient is φ = 8880287616.

The previous prime is 13320431429. The next prime is 13320431459. The reversal of 13320431433 is 33413402331.

It can be written as a sum of positive squares in only one way, i.e., 12478677264 + 841754169 = 111708^2 + 29013^2 .

It is not a de Polignac number, because 13320431433 - 2² = 13320431429 is a prime.

It is a super-2 number, since 2×13320431433² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13320431397 and 13320431406.

It is not an unprimeable number, because it can be changed into a prime (13320431533) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 740023960 + ... + 740023977.

Almost surely, 2^13320431433 is an apocalyptic number.

It is an amenable number.

13320431433 is a deficient number, since it is larger than the sum of its proper divisors (5920191761).

13320431433 is a wasteful number, since it uses less digits than its factorization.

13320431433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1480047943 (or 1480047940 counting only the distinct ones).

The product of its (nonzero) digits is 7776, while the sum is 27.

Adding to 13320431433 its reverse (33413402331), we get a palindrome (46733833764).

The spelling of 13320431433 in words is "thirteen billion, three hundred twenty million, four hundred thirty-one thousand, four hundred thirty-three".