Base | Representation |
---|---|
bin | 1100000111010110011110… |
… | …1111001010000001010011 |
3 | 1202011102100221121022021202 |
4 | 3001311213233022001103 |
5 | 3221220222100444310 |
6 | 44155153425141415 |
7 | 2543240525560655 |
oct | 301654757120123 |
9 | 52142327538252 |
10 | 13320433999955 |
11 | 4276189803665 |
12 | 15b170a48a86b |
13 | 75815b078a54 |
14 | 3409d8d446d5 |
15 | 181765c3e3a5 |
hex | c1d67bca053 |
13320433999955 has 8 divisors (see below), whose sum is σ = 16053123894912. Its totient is φ = 10610611803328.
The previous prime is 13320433999891. The next prime is 13320433999997. The reversal of 13320433999955 is 55999933402331.
13320433999955 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13320433999955 - 26 = 13320433999891 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13320433999891 and 13320433999900.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 5716923299 + ... + 5716925628.
It is an arithmetic number, because the mean of its divisors is an integer number (2006640486864).
Almost surely, 213320433999955 is an apocalyptic number.
13320433999955 is a deficient number, since it is larger than the sum of its proper divisors (2732689894957).
13320433999955 is a wasteful number, since it uses less digits than its factorization.
13320433999955 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11433849165.
The product of its (nonzero) digits is 106288200, while the sum is 65.
The spelling of 13320433999955 in words is "thirteen trillion, three hundred twenty billion, four hundred thirty-three million, nine hundred ninety-nine thousand, nine hundred fifty-five".
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