Base | Representation |
---|---|
bin | 11000110011111011… |
… | …10100111110001001 |
3 | 1021101022221112201212 |
4 | 30121331310332021 |
5 | 204240024240131 |
6 | 10041441222505 |
7 | 651044502464 |
oct | 143175647611 |
9 | 37338845655 |
10 | 13320540041 |
11 | 5716108986 |
12 | 26b9031a35 |
13 | 1343911973 |
14 | 9051682db |
15 | 52e66ba2b |
hex | 319f74f89 |
13320540041 has 4 divisors (see below), whose sum is σ = 13321080192. Its totient is φ = 13319999892.
The previous prime is 13320539971. The next prime is 13320540059. The reversal of 13320540041 is 14004502331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14004502331 = 37 ⋅378500063.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13320540041 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 13320539989 and 13320540016.
It is not an unprimeable number, because it can be changed into a prime (13320540241) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 231221 + ... + 283026.
It is an arithmetic number, because the mean of its divisors is an integer number (3330270048).
Almost surely, 213320540041 is an apocalyptic number.
It is an amenable number.
13320540041 is a deficient number, since it is larger than the sum of its proper divisors (540151).
13320540041 is an equidigital number, since it uses as much as digits as its factorization.
13320540041 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 540150.
The product of its (nonzero) digits is 1440, while the sum is 23.
The spelling of 13320540041 in words is "thirteen billion, three hundred twenty million, five hundred forty thousand, forty-one".
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