1332110221131 has 4 divisors (see below), whose sum is σ = 1776146961512. Its totient is φ = 888073480752.

The previous prime is 1332110221069. The next prime is 1332110221153. The reversal of 1332110221131 is 1311220112331.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 1332110221131 - 2⁹ = 1332110220619 is a prime.

It is a super-2 number, since 2×1332110221131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1332110221098 and 1332110221107.

It is not an unprimeable number, because it can be changed into a prime (1332110221181) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 222018370186 + ... + 222018370191.

It is an arithmetic number, because the mean of its divisors is an integer number (444036740378).

Almost surely, 2^{1332110221131} is an apocalyptic number.

1332110221131 is a deficient number, since it is larger than the sum of its proper divisors (444036740381).

1332110221131 is an equidigital number, since it uses as much as digits as its factorization.

1332110221131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 444036740380.

The product of its (nonzero) digits is 216, while the sum is 21.

Adding to 1332110221131 its reverse (1311220112331), we get a palindrome (2643330333462).

The spelling of 1332110221131 in words is "one trillion, three hundred thirty-two billion, one hundred ten million, two hundred twenty-one thousand, one hundred thirty-one".