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1332114112145 = 5266422822429
BaseRepresentation
bin10011011000101000001…
…100000011111010010001
311201100102022201101021002
4103120220030003322101
5133311132203042040
62455544220311345
7165146013061445
oct23305014037221
94640368641232
101332114112145
11473a45762a43
1219620a3a2555
139880547b86b
14486906b4825
15249b8452a15
hex13628303e91

1332114112145 has 4 divisors (see below), whose sum is σ = 1598536934580. Its totient is φ = 1065691289712.

The previous prime is 1332114112139. The next prime is 1332114112177. The reversal of 1332114112145 is 5412114112331.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 411980408449 + 920133703696 = 641857^2 + 959236^2 .

It is a cyclic number.

It is not a de Polignac number, because 1332114112145 - 220 = 1332113063569 is a prime.

It is a Curzon number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 133211411210 + ... + 133211411219.

It is an arithmetic number, because the mean of its divisors is an integer number (399634233645).

Almost surely, 21332114112145 is an apocalyptic number.

It is an amenable number.

1332114112145 is a deficient number, since it is larger than the sum of its proper divisors (266422822435).

1332114112145 is an equidigital number, since it uses as much as digits as its factorization.

1332114112145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 266422822434.

The product of its digits is 2880, while the sum is 29.

Adding to 1332114112145 its reverse (5412114112331), we get a palindrome (6744228224476).

The spelling of 1332114112145 in words is "one trillion, three hundred thirty-two billion, one hundred fourteen million, one hundred twelve thousand, one hundred forty-five".

Divisors: 1 5 266422822429 1332114112145