133213113000001 has 4 divisors (see below), whose sum is σ = 133213743540400. Its totient is φ = 133212482459604.

The previous prime is 133213112999963. The next prime is 133213113000017. The reversal of 133213113000001 is 100000311312331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133213113000001 - 2¹¹ = 133213112997953 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133213113000031) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 314953191 + ... + 315375868.

It is an arithmetic number, because the mean of its divisors is an integer number (33303435885100).

Almost surely, 2^{133213113000001} is an apocalyptic number.

It is an amenable number.

133213113000001 is a deficient number, since it is larger than the sum of its proper divisors (630540399).

133213113000001 is an equidigital number, since it uses as much as digits as its factorization.

133213113000001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 630540398.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 133213113000001 its reverse (100000311312331), we get a palindrome (233213424312332).

The spelling of 133213113000001 in words is "one hundred thirty-three trillion, two hundred thirteen billion, one hundred thirteen million, one", and thus it is an aban number.