13321442031041 has 4 divisors (see below), whose sum is σ = 13321449331284. Its totient is φ = 13321434730800.

The previous prime is 13321442031017. The next prime is 13321442031049. The reversal of 13321442031041 is 14013024412331.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It can be written as a sum of positive squares in 2 ways, for example, as 7328390410000 + 5993051621041 = 2707100^2 + 2448071^2 .

It is a cyclic number.

It is not a de Polignac number, because 13321442031041 - 2²² = 13321437836737 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13321442030995 and 13321442031013.

It is not an unprimeable number, because it can be changed into a prime (13321442031049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1758971 + ... + 5453151.

It is an arithmetic number, because the mean of its divisors is an integer number (3330362332821).

Almost surely, 2^{13321442031041} is an apocalyptic number.

It is an amenable number.

13321442031041 is a deficient number, since it is larger than the sum of its proper divisors (7300243).

13321442031041 is an equidigital number, since it uses as much as digits as its factorization.

13321442031041 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7300242.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13321442031041 its reverse (14013024412331), we get a palindrome (27334466443372).

The spelling of 13321442031041 in words is "thirteen trillion, three hundred twenty-one billion, four hundred forty-two million, thirty-one thousand, forty-one".