Base | Representation |
---|---|
bin | 1100000111011100010101… |
… | …0100010001010010000001 |
3 | 1202011120102100212002100010 |
4 | 3001313011110101102001 |
5 | 3221231431011310423 |
6 | 44200013312015133 |
7 | 2543324451464031 |
oct | 301670524212201 |
9 | 52146370762303 |
10 | 13322004010113 |
11 | 4276914a61517 |
12 | 15b1a882314a9 |
13 | 75834b411346 |
14 | 340b0766d8c1 |
15 | 1818089b7693 |
hex | c1dc5511481 |
13322004010113 has 16 divisors (see below), whose sum is σ = 17979535215936. Its totient is φ = 8772938395200.
The previous prime is 13322004010093. The next prime is 13322004010199. The reversal of 13322004010113 is 31101040022331.
It is not a de Polignac number, because 13322004010113 - 220 = 13322002961537 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13322004010113.
It is not an unprimeable number, because it can be changed into a prime (13322000010113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 2676570 + ... + 5814467.
It is an arithmetic number, because the mean of its divisors is an integer number (1123720950996).
Almost surely, 213322004010113 is an apocalyptic number.
It is an amenable number.
13322004010113 is a deficient number, since it is larger than the sum of its proper divisors (4657531205823).
13322004010113 is an equidigital number, since it uses as much as digits as its factorization.
13322004010113 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8497424.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13322004010113 its reverse (31101040022331), we get a palindrome (44423044032444).
The spelling of 13322004010113 in words is "thirteen trillion, three hundred twenty-two billion, four million, ten thousand, one hundred thirteen".
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