Base | Representation |
---|---|
bin | 11110010010101000010101… |
… | …010111011001101100001011 |
3 | 122110200212101010110121221212 |
4 | 132102220111113121230023 |
5 | 114430200421413342103 |
6 | 1151201103304523335 |
7 | 40026642531224462 |
oct | 3622502527315413 |
9 | 573625333417855 |
10 | 133221654043403 |
11 | 394a2a93698442 |
12 | 12b372ba48054b |
13 | 5944995687593 |
14 | 24c7d68dbd9d9 |
15 | 10606033047d8 |
hex | 792a155d9b0b |
133221654043403 has 4 divisors (see below), whose sum is σ = 133250053462728. Its totient is φ = 133193254624080.
The previous prime is 133221654043367. The next prime is 133221654043421. The reversal of 133221654043403 is 304340456122331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133221654043403 - 236 = 133152934566667 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133221654043603) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14199702626 + ... + 14199712007.
It is an arithmetic number, because the mean of its divisors is an integer number (33312513365682).
Almost surely, 2133221654043403 is an apocalyptic number.
133221654043403 is a deficient number, since it is larger than the sum of its proper divisors (28399419325).
133221654043403 is an equidigital number, since it uses as much as digits as its factorization.
133221654043403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 28399419324.
The product of its (nonzero) digits is 622080, while the sum is 41.
The spelling of 133221654043403 in words is "one hundred thirty-three trillion, two hundred twenty-one billion, six hundred fifty-four million, forty-three thousand, four hundred three".
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