Base | Representation |
---|---|
bin | 11000110100001001… |
… | …01111011000010001 |
3 | 1021101110100121110211 |
4 | 30122010233120101 |
5 | 204241010232040 |
6 | 10041544124121 |
7 | 651066060544 |
oct | 143204573021 |
9 | 37343317424 |
10 | 13322352145 |
11 | 5717136393 |
12 | 26b9766641 |
13 | 13440c770b |
14 | 9054ba85b |
15 | 52e8c88ea |
hex | 31a12f611 |
13322352145 has 8 divisors (see below), whose sum is σ = 16502526720. Its totient is φ = 10314078960.
The previous prime is 13322352143. The next prime is 13322352163. The reversal of 13322352145 is 54125322331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13322352145 - 21 = 13322352143 is a prime.
It is a super-2 number, since 2×133223521452 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is not an unprimeable number, because it can be changed into a prime (13322352143) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 42975175 + ... + 42975484.
It is an arithmetic number, because the mean of its divisors is an integer number (2062815840).
Almost surely, 213322352145 is an apocalyptic number.
It is an amenable number.
13322352145 is a deficient number, since it is larger than the sum of its proper divisors (3180174575).
13322352145 is an equidigital number, since it uses as much as digits as its factorization.
13322352145 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 85950695.
The product of its digits is 21600, while the sum is 31.
Adding to 13322352145 its reverse (54125322331), we get a palindrome (67447674476).
The spelling of 13322352145 in words is "thirteen billion, three hundred twenty-two million, three hundred fifty-two thousand, one hundred forty-five".
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