Base | Representation |
---|---|
bin | 111110000010100100… |
… | …0101101101100000011 |
3 | 110201220001001012101111 |
4 | 1330011020231230003 |
5 | 4140323410002142 |
6 | 141112144344151 |
7 | 12424365434245 |
oct | 1740510555403 |
9 | 421801035344 |
10 | 133230156547 |
11 | 51558a4a5a4 |
12 | 219a2615057 |
13 | c743171677 |
14 | 663c4a4095 |
15 | 36eb71be17 |
hex | 1f0522db03 |
133230156547 has 16 divisors (see below), whose sum is σ = 137124785952. Its totient is φ = 129392536320.
The previous prime is 133230156529. The next prime is 133230156559. The reversal of 133230156547 is 745651032331.
It is not a de Polignac number, because 133230156547 - 215 = 133230123779 is a prime.
It is a super-2 number, since 2×1332301565472 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133230151547) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10104223 + ... + 10117399.
It is an arithmetic number, because the mean of its divisors is an integer number (8570299122).
Almost surely, 2133230156547 is an apocalyptic number.
133230156547 is a deficient number, since it is larger than the sum of its proper divisors (3894629405).
133230156547 is a wasteful number, since it uses less digits than its factorization.
133230156547 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 15318.
The product of its (nonzero) digits is 226800, while the sum is 40.
Adding to 133230156547 its reverse (745651032331), we get a palindrome (878881188878).
The spelling of 133230156547 in words is "one hundred thirty-three billion, two hundred thirty million, one hundred fifty-six thousand, five hundred forty-seven".
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