Base | Representation |
---|---|
bin | 11000110100100000… |
… | …11000010011010001 |
3 | 1021101200002121221020 |
4 | 30122100120103101 |
5 | 204242300401340 |
6 | 10042133350053 |
7 | 651134026302 |
oct | 143220302321 |
9 | 37350077836 |
10 | 13325403345 |
11 | 571892a841 |
12 | 26ba798329 |
13 | 1344925467 |
14 | 905a727a9 |
15 | 52eccc9d0 |
hex | 31a4184d1 |
13325403345 has 8 divisors (see below), whose sum is σ = 21320645376. Its totient is φ = 7106881776.
The previous prime is 13325403341. The next prime is 13325403359. The reversal of 13325403345 is 54330452331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13325403345 - 22 = 13325403341 is a prime.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (13325403341) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 444180097 + ... + 444180126.
It is an arithmetic number, because the mean of its divisors is an integer number (2665080672).
Almost surely, 213325403345 is an apocalyptic number.
13325403345 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
13325403345 is a deficient number, since it is larger than the sum of its proper divisors (7995242031).
13325403345 is an equidigital number, since it uses as much as digits as its factorization.
13325403345 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 888360231.
The product of its (nonzero) digits is 64800, while the sum is 33.
Adding to 13325403345 its reverse (54330452331), we get a palindrome (67655855676).
The spelling of 13325403345 in words is "thirteen billion, three hundred twenty-five million, four hundred three thousand, three hundred forty-five".
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