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13325455131 = 34441818377
BaseRepresentation
bin11000110100100001…
…00100111100011011
31021101200012020222020
430122100210330123
5204242304031011
610042134425523
7651134333262
oct143220447433
937350166866
1013325455131
11571896573a
1226ba8022a3
131344942bc1
14905a875d9
1552ecdd006
hex31a424f1b

13325455131 has 4 divisors (see below), whose sum is σ = 17767273512. Its totient is φ = 8883636752.

The previous prime is 13325455123. The next prime is 13325455147. The reversal of 13325455131 is 13155452331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13325455131 - 23 = 13325455123 is a prime.

It is a super-2 number, since 2×133254551312 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13325455092 and 13325455101.

It is not an unprimeable number, because it can be changed into a prime (13325455111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2220909186 + ... + 2220909191.

It is an arithmetic number, because the mean of its divisors is an integer number (4441818378).

Almost surely, 213325455131 is an apocalyptic number.

13325455131 is a deficient number, since it is larger than the sum of its proper divisors (4441818381).

13325455131 is an equidigital number, since it uses as much as digits as its factorization.

13325455131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4441818380.

The product of its digits is 27000, while the sum is 33.

The spelling of 13325455131 in words is "thirteen billion, three hundred twenty-five million, four hundred fifty-five thousand, one hundred thirty-one".

Divisors: 1 3 4441818377 13325455131