Base | Representation |
---|---|
bin | 111110000011110000… |
… | …0111110000010010011 |
3 | 110201222211010222112010 |
4 | 1330013200332002103 |
5 | 4140414114210040 |
6 | 141120132034003 |
7 | 12425361620241 |
oct | 1740740760223 |
9 | 421884128463 |
10 | 133270069395 |
11 | 51579530721 |
12 | 219b3a62903 |
13 | c74b507638 |
14 | 66438d3791 |
15 | 36eeea2e80 |
hex | 1f0783e093 |
133270069395 has 8 divisors (see below), whose sum is σ = 213232111056. Its totient is φ = 71077370336.
The previous prime is 133270069381. The next prime is 133270069403. The reversal of 133270069395 is 593960072331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 133270069395 - 28 = 133270069139 is a prime.
It is a super-2 number, since 2×1332700693952 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4442335632 + ... + 4442335661.
It is an arithmetic number, because the mean of its divisors is an integer number (26654013882).
Almost surely, 2133270069395 is an apocalyptic number.
133270069395 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
133270069395 is a deficient number, since it is larger than the sum of its proper divisors (79962041661).
133270069395 is an equidigital number, since it uses as much as digits as its factorization.
133270069395 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 8884671301.
The product of its (nonzero) digits is 918540, while the sum is 48.
The spelling of 133270069395 in words is "one hundred thirty-three billion, two hundred seventy million, sixty-nine thousand, three hundred ninety-five".
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