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133270069395 = 358884671293
BaseRepresentation
bin111110000011110000…
…0111110000010010011
3110201222211010222112010
41330013200332002103
54140414114210040
6141120132034003
712425361620241
oct1740740760223
9421884128463
10133270069395
1151579530721
12219b3a62903
13c74b507638
1466438d3791
1536eeea2e80
hex1f0783e093

133270069395 has 8 divisors (see below), whose sum is σ = 213232111056. Its totient is φ = 71077370336.

The previous prime is 133270069381. The next prime is 133270069403. The reversal of 133270069395 is 593960072331.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 133270069395 - 28 = 133270069139 is a prime.

It is a super-2 number, since 2×1332700693952 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4442335632 + ... + 4442335661.

It is an arithmetic number, because the mean of its divisors is an integer number (26654013882).

Almost surely, 2133270069395 is an apocalyptic number.

133270069395 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

133270069395 is a deficient number, since it is larger than the sum of its proper divisors (79962041661).

133270069395 is an equidigital number, since it uses as much as digits as its factorization.

133270069395 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 8884671301.

The product of its (nonzero) digits is 918540, while the sum is 48.

The spelling of 133270069395 in words is "one hundred thirty-three billion, two hundred seventy million, sixty-nine thousand, three hundred ninety-five".

Divisors: 1 3 5 15 8884671293 26654013879 44423356465 133270069395