Base | Representation |
---|---|
bin | 10011011001011101000… |
… | …111000101011011110001 |
3 | 11201102201012102202120122 |
4 | 103121131013011123301 |
5 | 133314442003000423 |
6 | 2500212255020025 |
7 | 165210014023220 |
oct | 23313507053361 |
9 | 4642635382518 |
10 | 1333002000113 |
11 | 474360972353 |
12 | 19641780a615 |
13 | 989173c4264 |
14 | 4873659acb7 |
15 | 24a1b38a8c8 |
hex | 1365d1c56f1 |
1333002000113 has 8 divisors (see below), whose sum is σ = 1528393175232. Its totient is φ = 1138851404496.
The previous prime is 1333002000079. The next prime is 1333002000173. The reversal of 1333002000113 is 3110002003331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1333002000113 - 210 = 1333001999089 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1333002000091 and 1333002000100.
It is not an unprimeable number, because it can be changed into a prime (1333002000173) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 310142570 + ... + 310146867.
It is an arithmetic number, because the mean of its divisors is an integer number (191049146904).
Almost surely, 21333002000113 is an apocalyptic number.
It is an amenable number.
1333002000113 is a deficient number, since it is larger than the sum of its proper divisors (195391175119).
1333002000113 is an equidigital number, since it uses as much as digits as its factorization.
1333002000113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 620289751.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 1333002000113 its reverse (3110002003331), we get a palindrome (4443004003444).
The spelling of 1333002000113 in words is "one trillion, three hundred thirty-three billion, two million, one hundred thirteen", and thus it is an aban number.
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