Base | Representation |
---|---|
bin | 11110010011110010100001… |
… | …011011001000111101101011 |
3 | 122110222110222201022100111001 |
4 | 132103302201123020331223 |
5 | 114433002042142320120 |
6 | 1151301440010015431 |
7 | 40035462544245025 |
oct | 3623624133107553 |
9 | 573873881270431 |
10 | 133301313245035 |
11 | 39523851194681 |
12 | 12b4a830117577 |
13 | 594c34c008550 |
14 | 24cbb647a5015 |
15 | 1062716905e0a |
hex | 793ca16c8f6b |
133301313245035 has 16 divisors (see below), whose sum is σ = 172269304605216. Its totient is φ = 98436183084288.
The previous prime is 133301313245027. The next prime is 133301313245063. The reversal of 133301313245035 is 530542313103331.
It is a cyclic number.
It is not a de Polignac number, because 133301313245035 - 23 = 133301313245027 is a prime.
It is a super-2 number, since 2×1333013132450352 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 133301313244985 and 133301313245003.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 14032954 + ... + 21529663.
It is an arithmetic number, because the mean of its divisors is an integer number (10766831537826).
Almost surely, 2133301313245035 is an apocalyptic number.
133301313245035 is a deficient number, since it is larger than the sum of its proper divisors (38967991360181).
133301313245035 is a wasteful number, since it uses less digits than its factorization.
133301313245035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 35620302.
The product of its (nonzero) digits is 145800, while the sum is 37.
Adding to 133301313245035 its reverse (530542313103331), we get a palindrome (663843626348366).
The spelling of 133301313245035 in words is "one hundred thirty-three trillion, three hundred one billion, three hundred thirteen million, two hundred forty-five thousand, thirty-five".
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