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133302020113 = 654720360779
BaseRepresentation
bin111110000100101101…
…0110110100000010001
3110202002001021020200001
41330021122312200101
54141000304120423
6141123232530001
712426230322103
oct1741132664021
9422061236601
10133302020113
1151595573779
1221a026b0901
13c7550134a2
146647c4d573
153702bb4cad
hex1f096b6811

133302020113 has 4 divisors (see below), whose sum is σ = 133322387440. Its totient is φ = 133281652788.

The previous prime is 133302020101. The next prime is 133302020129. The reversal of 133302020113 is 311020203331.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 133302020113 - 217 = 133301889041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133302060113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 10173843 + ... + 10186936.

It is an arithmetic number, because the mean of its divisors is an integer number (33330596860).

Almost surely, 2133302020113 is an apocalyptic number.

It is an amenable number.

133302020113 is a deficient number, since it is larger than the sum of its proper divisors (20367327).

133302020113 is an equidigital number, since it uses as much as digits as its factorization.

133302020113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 20367326.

The product of its (nonzero) digits is 324, while the sum is 19.

Adding to 133302020113 its reverse (311020203331), we get a palindrome (444322223444).

The spelling of 133302020113 in words is "one hundred thirty-three billion, three hundred two million, twenty thousand, one hundred thirteen".

Divisors: 1 6547 20360779 133302020113