133310030120131 has 4 divisors (see below), whose sum is σ = 133506943016112. Its totient is φ = 133113117224152.

The previous prime is 133310030120123. The next prime is 133310030120177. The reversal of 133310030120131 is 131021030013331.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 133310030120131 - 2³ = 133310030120123 is a prime.

It is a super-2 number, since 2×133310030120131² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (133310030123131) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 98456446975 + ... + 98456448328.

It is an arithmetic number, because the mean of its divisors is an integer number (33376735754028).

Almost surely, 2^{133310030120131} is an apocalyptic number.

133310030120131 is a deficient number, since it is larger than the sum of its proper divisors (196912895981).

133310030120131 is an equidigital number, since it uses as much as digits as its factorization.

133310030120131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 196912895980.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 133310030120131 its reverse (131021030013331), we get a palindrome (264331060133462).

The spelling of 133310030120131 in words is "one hundred thirty-three trillion, three hundred ten billion, thirty million, one hundred twenty thousand, one hundred thirty-one".