Base | Representation |
---|---|
bin | 111110000100111110… |
… | …1001010000010001001 |
3 | 110202002200012010120222 |
4 | 1330021331022002021 |
5 | 4141010104404001 |
6 | 141124153355425 |
7 | 12426366625325 |
oct | 1741175120211 |
9 | 422080163528 |
10 | 133311013001 |
11 | 5159a656211 |
12 | 21a05708b75 |
13 | c756b4181a |
14 | 6649110985 |
15 | 370388e61b |
hex | 1f09f4a089 |
133311013001 has 4 divisors (see below), whose sum is σ = 133328600832. Its totient is φ = 133293425172.
The previous prime is 133311012997. The next prime is 133311013063. The reversal of 133311013001 is 100310113331.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 133311013001 - 22 = 133311012997 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133311013601) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8782541 + ... + 8797706.
It is an arithmetic number, because the mean of its divisors is an integer number (33332150208).
Almost surely, 2133311013001 is an apocalyptic number.
It is an amenable number.
133311013001 is a deficient number, since it is larger than the sum of its proper divisors (17587831).
133311013001 is an equidigital number, since it uses as much as digits as its factorization.
133311013001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 17587830.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 133311013001 its reverse (100310113331), we get a palindrome (233621126332).
The spelling of 133311013001 in words is "one hundred thirty-three billion, three hundred eleven million, thirteen thousand, one".
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