Base | Representation |
---|---|
bin | 11110010011111011100100… |
… | …101001110100001001100011 |
3 | 122111000102001222011112101102 |
4 | 132103323210221310021203 |
5 | 114433131442430200003 |
6 | 1151310124153225015 |
7 | 40036255424533511 |
oct | 3623734451641143 |
9 | 574012058145342 |
10 | 133311031100003 |
11 | 3952798870a979 |
12 | 12b506a270216b |
13 | 595023a409ba3 |
14 | 24cc4072814b1 |
15 | 1062ad4b30588 |
hex | 793ee4a74263 |
133311031100003 has 4 divisors (see below), whose sum is σ = 133314366333768. Its totient is φ = 133307695866240.
The previous prime is 133311031099979. The next prime is 133311031100087. The reversal of 133311031100003 is 300001130113331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133311031100003 - 220 = 133311030051427 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133311031102003) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1667556926 + ... + 1667636867.
It is an arithmetic number, because the mean of its divisors is an integer number (33328591583442).
Almost surely, 2133311031100003 is an apocalyptic number.
133311031100003 is a deficient number, since it is larger than the sum of its proper divisors (3335233765).
133311031100003 is an equidigital number, since it uses as much as digits as its factorization.
133311031100003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3335233764.
The product of its (nonzero) digits is 243, while the sum is 20.
Adding to 133311031100003 its reverse (300001130113331), we get a palindrome (433312161213334).
The spelling of 133311031100003 in words is "one hundred thirty-three trillion, three hundred eleven billion, thirty-one million, one hundred thousand, three".
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