Base | Representation |
---|---|
bin | 11000110101001100… |
… | …01000000100101001 |
3 | 1021102001211020211010 |
4 | 30122212020010221 |
5 | 204300230312131 |
6 | 10042455454133 |
7 | 651233341353 |
oct | 143246100451 |
9 | 37361736733 |
10 | 13331104041 |
11 | 5721073862 |
12 | 2700687349 |
13 | 1345b70158 |
14 | 9067180d3 |
15 | 530556b46 |
hex | 31a988129 |
13331104041 has 8 divisors (see below), whose sum is σ = 17782108864. Its totient is φ = 8883750960.
The previous prime is 13331104019. The next prime is 13331104091. The reversal of 13331104041 is 14040113331.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13331104041 - 219 = 13330579753 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13331103999 and 13331104017.
It is not an unprimeable number, because it can be changed into a prime (13331104001) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 904405 + ... + 919026.
It is an arithmetic number, because the mean of its divisors is an integer number (2222763608).
Almost surely, 213331104041 is an apocalyptic number.
It is an amenable number.
13331104041 is a deficient number, since it is larger than the sum of its proper divisors (4451004823).
13331104041 is a wasteful number, since it uses less digits than its factorization.
13331104041 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1825871.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13331104041 its reverse (14040113331), we get a palindrome (27371217372).
The spelling of 13331104041 in words is "thirteen billion, three hundred thirty-one million, one hundred four thousand, forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.140 sec. • engine limits •