Base | Representation |
---|---|
bin | 111110000100111111… |
… | …0010000000110101011 |
3 | 110202002200201201021222 |
4 | 1330021332100012223 |
5 | 4141010143100021 |
6 | 141124203452255 |
7 | 12426402232151 |
oct | 1741176200653 |
9 | 422080651258 |
10 | 133311300011 |
11 | 5159a83190a |
12 | 21a0582708b |
13 | c756c12356 |
14 | 66491873d1 |
15 | 37038e96ab |
hex | 1f09f901ab |
133311300011 has 4 divisors (see below), whose sum is σ = 133400235000. Its totient is φ = 133222365024.
The previous prime is 133311299969. The next prime is 133311300019. The reversal of 133311300011 is 110003113331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133311300011 - 226 = 133244191147 is a prime.
It is a super-5 number, since 5×1333113000115 (a number of 57 digits) contains 55555 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133311300019) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44465246 + ... + 44468243.
It is an arithmetic number, because the mean of its divisors is an integer number (33350058750).
Almost surely, 2133311300011 is an apocalyptic number.
133311300011 is a deficient number, since it is larger than the sum of its proper divisors (88934989).
133311300011 is an equidigital number, since it uses as much as digits as its factorization.
133311300011 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 88934988.
The product of its (nonzero) digits is 81, while the sum is 17.
Adding to 133311300011 its reverse (110003113331), we get a palindrome (243314413342).
The spelling of 133311300011 in words is "one hundred thirty-three billion, three hundred eleven million, three hundred thousand, eleven".
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