Base | Representation |
---|---|
bin | 11110010011111100100101… |
… | …000110000000011001001011 |
3 | 122111000111212022111201200122 |
4 | 132103330211012000121023 |
5 | 114433141201212411021 |
6 | 1151310423333453455 |
7 | 40036324263154046 |
oct | 3623744506003113 |
9 | 574014768451618 |
10 | 133312112232011 |
11 | 39528392a083a9 |
12 | 12b509447a128b |
13 | 59503803b277b |
14 | 24cc4aaaabc5d |
15 | 1062b499dabab |
hex | 793f2518064b |
133312112232011 has 4 divisors (see below), whose sum is σ = 133315349811432. Its totient is φ = 133308874652592.
The previous prime is 133312112231983. The next prime is 133312112232023. The reversal of 133312112232011 is 110232211213331.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 133312112232011 - 214 = 133312112215627 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (133312112232311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1618727945 + ... + 1618810298.
It is an arithmetic number, because the mean of its divisors is an integer number (33328837452858).
Almost surely, 2133312112232011 is an apocalyptic number.
133312112232011 is a deficient number, since it is larger than the sum of its proper divisors (3237579421).
133312112232011 is an equidigital number, since it uses as much as digits as its factorization.
133312112232011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3237579420.
The product of its (nonzero) digits is 1296, while the sum is 26.
Adding to 133312112232011 its reverse (110232211213331), we get a palindrome (243544323445342).
The spelling of 133312112232011 in words is "one hundred thirty-three trillion, three hundred twelve billion, one hundred twelve million, two hundred thirty-two thousand, eleven".
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